avatarBella Lockhart

Summary

The article presents a geometry puzzle involving circles and a square, and provides a step-by-step solution to find the area of the square.

Abstract

The article titled "Are You Smart Enough To Find The Area?" presents an interesting geometry puzzle involving four circles of radius 1, each tangent to two sides of a square and externally tangent to a circle of radius 2. The solution to the puzzle involves constructing an isosceles right triangle with vertices at the centers of the circle of radius 2 and two of the circles of radius 1, and using Pythagoras' Theorem to find the length of the hypotenuse. The length of a side of the square is then determined by adding 2 to the length of the hypotenuse, and the area of the square is calculated by squaring the length of the side.

Opinions

  • The author believes that the puzzle can be solved by anyone who knows basic geometry and has some imagination.
  • The author encourages readers to pause the article and try solving the puzzle themselves before reading the solution.
  • The author finds the solution to the puzzle "amazing" and invites readers to share their thought process in the comments section.
  • The author recommends a list of the best math puzzles on Medium and provides a link to subscribe to their newsletter.
  • The author expresses gratitude to readers for their support and encourages them to buy them a coffee if they found the article insightful.

Are You Smart Enough To Find The Area?

An Interesting Geometry Puzzle

Image by the author

There are four circles of radius 1, which are each tangent to two sides of a square and externally tangent to a circle of radius 2.

So long you know some basic geometry and have some imagination, you will be able to crack this puzzle 🧩

Here’s a hint: connect the circles …

I recommend you pause the article, grab your pen and paper, and give this a go. When you are ready, keep reading for the solution! ✒️

Solution

We let s be the length of a side of the square.

We then construct an isosceles right triangle with vertices at the centers of the circle of radius 2 and two of the circles of radius 1.

like this!

This triangle has legs of length 3.

Using Pythagoras’ Theorem, we have h² = 3² + 3²

So the hypotenuse has length 3√2.

The length of a side of the square is 2 more than the length of this hypotenuse, as indicated by the two blue arrows below.

So we have the side length of the square as

Squaring it, we get

And that’s the area.

How amazing 👧

What was your thought process this time? Comment down below, I am eager to know :) 💞

Save and share the following list for the best math puzzles on Medium👇

Thank you for reading. Don’t forget to clap the article if you find it insightful.

tip me 💘, i will thank you a million times

I put a lot of effort into writing every article for you, so please buy me a coffee☕ if you are feeling generous. It’s a great way to support my writing as well as my personal and academic life.

Love, Bella ❤️

Math
Science
Education
Artificial Intelligence
Data Science
Recommended from ReadMedium